more info!
How do you calculate the retention time of your filter? Doing the Maths
This is determined by the flow rate and the volume of water in the filter. If water output from the filter is 2,000 gallons/hour and the filter contains 500 gallons (when full of media) of water then:
filter retention time = filter size / pump rate
so, in our example:
retention time = 500 (gallons) / 2000 (gallons per hour flow rate) = 0.25 hours (which is 15 minutes).
So a given sample of water will take 15 minutes to pass through the filter and back to the pond.
In the above, the filter capacity represents the amount of water in the filter - not the physical size of the filter, which will be greater.
The retention time and the size of the filter will depend to a very large extent on the type of filtration medium used.
A solid medium with low void space such as gravel will occupy much more filter space than large-pored, lightly packed media and therefore leads to a lower retention time.
More calculations!
Using our same example of a 500-gallon filter. If we now nearly fill it with gravel, the volume of water it will hold will be reduced substantially - maybe to as little as 150 to 200 gallons. Using the above example, the retention time of such a filter would now become;
200/2000 = 0.1 hours (6 minutes) or less
In comparison, if the same filter was filled instead with matting or plastic, there would be hardly any displacement and the filter will probably still hold in excess of 450 gallons, giving a retention time over double that of gravel. So a filter with a dense, low-void medium, such as gravel, will need to be substantially larger than one based on light-weight media, in order to achieve the same retention time, which explains why koi filters were traditionally so large.